TCS Recruitment Rounds PART-III

1.Written Test

2.Technical Interview

3.MR ( Managerial)

4. HR Interview

WRITTEN TEST :( ONLINE TEST)

Contains 3 sections

1) Verbal (Synonyms - Antonyms - Comprehension Passages)

2) Quantitative Aptitude

3) Critical Reasoning

SECTION-1(Verbal- 30 questions - 20 min)

1.Synonyms (Refer In GRE BARRONS 12th Edition )

2.Antonyms (Refer In GRE BARRONS 12th Edition (page no -126))

3. Passage completion

For more Question,Placement Papers Log on to http://topengineeringcollegesintamilnadu.blogspot.com/

61) The size of the bucket is N kb. The bucket fills at the rate of 0.1 kb per millisecond. A programmer sends a program to receiver. There it waits for 10 milliseconds. And response will be back to programmer in 20 milliseconds. How much time the program takes to get a response back to the programmer, after it is sent?

Ans: 30 milliseconds

62) A person who decided to go weekend trip should not exceed 8 hours driving in a day average speed of forward journey is 40 mph due to traffic in Sundays the return journey average speed is 30 mph. How far he can select a picnic spot.

Ans: Between 120 and 140 miles

63) Car is filled with four and half gallons of oil for full round trip. Fuel is taken 1/4 gallons more in going than coming. What is the fuel consumed in coming up.

Sol: Let fuel consumed in coming up is x.

Thus equation is: x+1.25x=4.5

Ans: 2gallons

64) 40% employees are male if 60% of supervisors are male so for 100% is 26.4%so the probability is ......

Ans: 0.264

65) Gavaskar average in first 50 innings was 50. After the 51st innings his average was 51 how many runs he made in the 51st innings

Sol: first 50 ings.- run= 50*50=2500

51st ings. - Avg 51. So total run =51*51=2601.

So run scored in that ings=2601-2500=101 runs.

Ans: 101 runs

66) Hansie made the following amounts in seven games of cricket in India: Rs.10, Rs.15, Rs.21, Rs.12, Rs.18, Rs.19 and Rs.17 (all figures in crores of course).Find his average earnings.

Ans: Rs.16 crore

67) Average of 5 numbers is -10 sum of 3 numbers is 16, what is the average of other two numbers?

Ans: -33

68) If A, B and C are the mechanisms used separately to reduce the wastage of fuel by 30%, 20% and 10%. What will be the fuel economy if they were used combined. Ans: 20%

69) In 80 coins one coin is counterfeit what is minimum number of weighing to find out counterfeit coin

Sol: the minimum number of weightings needed is just 5.as shown below

(1) 80->30-30

(2) 15-15

(3) 7-7

(4) 3-3

(5) 1-1

Ans: 5.

70) 2 oranges, 3 bananas and 4 apples cost Rs.15. 3 oranges, 2 bananas, and 1 apple costs Rs 10. What is the cost of 3 oranges, 3 bananas and 3 apples?

Sol: 2x+3y+4z=15

3x+2y+z=10

Adding

5x+5y+5z=25

x+y+z=5 that is for 1 orange, 1 banana and 1 apple requires 5Rs.

So for 3 orange, 3 bananas and 3 apples require 15Rs.

i.e. 3x+3y+3z=15

Ans: 15

71) In 8*8 chess board what is the total number of squares refers odele discovered that there are 204 squares on the board .We found that you would add the different squares

= 1 + 4 + 9 + 16+ 25 + 36 + 49 + 64. =204

Also in 3*3 tic tac toe board what is the total no of squares

Ans: 14 i.e. 9+4(bigger ones) +1 (biggest one)

If you get 100*100 board just use the formula the formula for the sum of the first n perfect squares is

n x (n + 1) x (2n + 1)

______________________

6

72) One fast typist type some matter in 2hr and another slow typist type the same matter in 3hr. If both do combine in how much time they will finish.

Sol: Faster one can do 1/2 of work in one hour slower one can do 1/3 of work in one hour both they do (1/2+1/3=5/6) the work in one hour. So work will b finished in 6/5=1.2 hour

i e 1 hour 12 min.

Ans: 1 hour 12 min.

73)If Rs20/- is available to pay for typing a research report & typist A produces 42 pages and typist B produces 28 pages. How much should typist A receive?

Sol: Find 42 % of 20 rs with respect to 70 (i.e. 28 + 42)

==> (42 * 20)/70 ==> 12 Rs

Ans: 12 Rs

74) In some game 139 members have participated every time one fellow will get bye what is the number of matches to choose the champion to be held?

Ans: 138 matches

(Explanation: since one player gets a bye in each round, he will reach the finals of the tournament without playing a match.

Therefore 137 matches should be played to determine the second finalist from the remaining 138 players (excluding the 1st player)

Therefore to determine the winner 138 matches should be played.)

75) ONE RECTANGULAR PLATE WITH LENGTH 8INCHES, BREADTH 11 INCHES AND 2 INCHES THICKNESS IS THERE.WHAT IS THE LENGTH OF THE CIRCULAR ROD WITH DIAMETER 8 INCHES AND EQUAL TO VOLUME OF RECTANGULAR PLATE?

Sol: Vol. of rect. plate= 8*11*2=176

Area of rod= (22/7)*(8/2)*(8/2) = (352/7)

Vol. of rod=area*length=vol. of plate

So length of rod= vol of plate/area=176/ (352/7) =3.5

Ans: 3.5

76) One tank will fill in 6 minutes at the rate of 3cu ft /min, length of tank is 4 ft and the width is 1/2 of length, what is the depth of the tank?

Ans: 3 ft 7.5 inches

77) A power unit is there by the bank of the river of 750 meters width. A cable is made from power unit to power a plant opposite to that of the river and 1500mts away from the power unit. The cost of the cable below water is Rs. 15/- per meter and cost of cable on the bank is Rs.12/- per meter. Find the total of laying the cable.

Ans: 1000 (24725 - cost) 20250

Ans: Rs. 22,500 (hint: the plant is on the other side of the plant i.e. it is not on the same side as the river)

78) The cost of one pencil, two pens and four erasers is Rs.22 while the cost of five pencils, four pens and two erasers is Rs.32.How much will three pencils, three pens and three erasers cost?

Sol :( let x b pencil, y b pen and z b eraser... u get x+2y+4z=22 and 5x+4y+2z=32 add 6x+6y+6z=54 div by 2 you get 27)

Ans: 27

79) A man has to get air-mail. He starts to go to airport on his motorbike. Plane comes early and the mail is sent by a horse-cart. The man meets the cart in the middle after half an hour. He takes the mail and returns back, by doing so, he saves twenty minutes. How early did the plane arrive?

Sol: Assume he started at 1:00, so at 1:30 he met cart .He returned home at 2:00.so it took him 1 hour for the total journey. By doing this he saved 20 min. So the actual time if the plane is not late is 1 hour and 20 min. So the actual time of plane is at 1:40.The cart traveled a time of 10 min before it met him. So the plane is 10 min early.

Ans: 10 min

80) Ram singh goes to his office in the city every day from his suburban house. His driver Mangaram drops him at the railway station in the morning and picks him up in the evening. Every evening Ram singh reaches the station at 5 o,clock. Mangaram also reaches at the same time. One day Ram singh started early from his office and came to the station at 4 o,clock. Not wanting to wait for the car he starts walking home. Mangaram starts at normal time, picks him up on the way and takes him back house, half an hour early. How much time did Ram singh walked?

81) 2 trees are there. One grows at 3/5 of the other. In 4 years total growth of the trees is 8 ft. what growth will smaller tree have in 2 years.

Sol: THE BIG TREE GROWS 8FT IN 4 YEARS=>THE BIG TREE GROWS 4FT IN 2 YEARS.WHEN WE DIVIDE 4FT/5=.8*3=>2.4

4 (x+ (3/5) x) =88x/5=2x=5/4

After 2 years x= (3/5)*(5/4)*2 =1.5 (less than 2 feet)

82) There is a six digit code. Its first two digits, multiplied by 3 gives all ones. And the next two digits multiplied by 6 give all twos. Remaining two digits multiplied by 9 gives all threes. Then what is the code?

Sol: Assume the digit xx xx xx (six digits)

First Two digit xx * 3=111

xx =111/3=37

(First two digits of 1 is not divisible by 3 so we can use 111)

Second Two digit xx*6=222

xx=222/6=37

(First two digits of 2 is not divisible by 6 so we can use 222)

Third Two digit xx*9=333

xx=333/9=37

(First two digits of 3 is not divisible by 9 so we can use 333)

83) There are 4 balls and 4 boxes of colors yellow, pink, red and green. Red ball is in a box whose color is same as that of the ball in a yellow box. Red box has green ball. In which box you find the yellow ball?

Sol: Yellow box can have either of pink/yellow balls.

if we put a yellow ball in "yellow" box then it would imply that "yellow" is also the color of the box which has the red ball(because according 2 d question,d box of the red ball n the ball in the yellow box have same color)

Thus this possibility is ruled out...

Therefore the ball in yellow box must be pink, hence the color of box contain in red ball is also pink....

=>the box color left out is "green", which is allotted to the only box left, the one which has yellow ball.

Ans: green

84) A bag contains 20 yellow balls, 10 green balls, 5 white balls, 8 black balls, and 1 red ball. How many minimum balls one should pick out so that to make sure the he gets at least 2 balls of same color.

Sol: suppose he picks 5 balls of all different colors then when he picks up the sixth one, it must match any on of the previously drawn ball color. Thus he must pick 6 balls

Ans: he should pick 6 balls totally.

85) WHAT IS THE NUMBER OF ZEROS AT THE END OF THE PRODUCT OF THE NUMBERS FROM 1 TO 100?

Sol: For every 5 in unit place one zero is added

so between 1 to 100 there are 10 nos like 5,15,25,..,95 which has 5 in unit place.

Similarly for every no divisible by 10 one zero is added in the answer so between 1 to 100 , 11 zeros are added

For 25, 50, 75 3 extra zeros are added

So total no of zeros are 10+11+3=24

86) There are two numbers in the ratio 8:9. If the smaller of the two numbers is increased by 12 and the larger number is reduced by 19 thee the ratio of the two numbers is 5:9.

Find the larger number?

Sol: 8x: 9x initially

8x+ 12: 9x - 19 = 5x: 9x

8x+12 = 5x

-> x = 4

9x = 36 (NOT SURE ABOUT THE ANSWER)

87) There are three different boxes A, B and C. Difference between weights of A and B is 3 kgs. And between B and C is 5 kgs. Then what is the maximum sum of the differences of all possible combinations when two boxes are taken each time

Sol: A-B = 3

B-c = 5

A-c = 8 so sum of diff = 8+3+5 = 16 kgs

88) A and B are shooters and having their exam. A and B fall short of 10 and 2 shots respectively to the qualifying mark. If each of them fired at least one shot and even by adding their total score together, they fall short of the qualifying mark, what is the qualifying mark?

Sol: Because each had at least 1 shot done so 10 + 1 = 11

And 9 + 2 = 11

So the ans is 11

89) A, B, C, and D tells the following times by looking at their watches. A tells it is 3 to 12. B tells it is 3 past 12. C tells it is 12:2. D tells it is half a dozen too soon to 12. No two watches show the same time. The difference between the watches is 2,3,4,5 respectively. Whose watch shows maximum time?

Sol: A shows 11:57, B shows 12:03, C shows 12:02 and D shows 11:06 therefore,

Max time is for B

90) Falling height is proportional to square of the time. One object falls 64cm in 2sec than in 6sec from how much height the object will fall.

Sol: The falling height is proportional to the square of the time.

Now, the falling height is 64cm at 2sec

So, the proportional constant is=64/ (2*2) =16;

So, at 6sec the object fall maximum (16*6*6) cm=576cm;

Now, the object may be situated at any where.

If it is>576 only that time the object falling 576cm within 6sec .Otherwise if it is situated

For more Question,Placement Papers Log on to http://topengineeringcollegesintamilnadu.blogspot.com/

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